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Arpit Bhola Tiwari
Asked: 2022-11-05T15:05:54+05:30 In:

The correct relationship between free energy change in a reaction and the corresponding equilibrium
constant K is
A. `-DeltaG^(@)= RT ln K`
B. `DeltaG= RT ln K`
C. `-DeltaG= RT ln K`
D. `DeltaG^(@)= RT ln K`

The correct relationship between free energy change in a reaction and the corresponding equilibrium
constant K is
A. `-DeltaG^(@)= RT ln K`
B. `DeltaG= RT ln K`
C. `-DeltaG= RT ln K`
D. `DeltaG^(@)= RT ln K`
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  1. Correct Answer – A
    `DeltaG^(@) = – RT In K `

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Subhash Kumar Kumer
Asked: 2022-11-05T05:07:53+05:30 In:

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is
A. `DeltaG=RTlnK_(c)`
B. `-DeltaG=RTlnK_(c)`
C. `DeltaG^(@)=RTlnK_(c)`
D. `-DeltaG^(@)=RTlnK_(c)`

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is
A. `DeltaG=RTlnK_(c)`
B. `-DeltaG=RTlnK_(c)`
C. `DeltaG^(@)=RTlnK_(c)`
D. `-DeltaG^(@)=RTlnK_(c)`
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  1. Correct Answer – D

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Giaan Prasad Sahota
Asked: 2022-11-02T17:02:15+05:30 In:

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is:
A. `DeltaG^(@)=RT ln K_(c)`
B. `-DeltaG^(@)=RT lnK_(c)`
C. `DeltaG=RT ln K_(c)`
D. `-DeltaG=RT lnK_(c)`

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is:
A. `DeltaG^(@)=RT ln K_(c)`
B. `-DeltaG^(@)=RT lnK_(c)`
C. `DeltaG=RT ln K_(c)`
D. `-DeltaG=RT lnK_(c)`
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  1. Correct Answer – b
    `DeltaG=DeltaG^(@)+RTln Q`, Where `Q` is reaction quotient , At equibrium `DeltaG=0` and `Q=K_(c) :. -DeltaG^(@)=RT ln K_(c)`

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