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Falguni Koshy
Asked: 2022-11-01T12:47:37+05:30 In:

tan70° = tan20°+2tan50°

tan70° = tan20°+2tan50°
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  1. Tan70=tan(20+50)Nd using the identity of tan(A+B)Tan70(1-tan20.tan50)=tan20+tan50Tan70-tan20.tan70.tan50=tan20+tan50And..tan70.tan20=tan70cot70=1NowTan70-tan50=tan20+tan50OrTan70=tan20+2tan50

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Suresh Lall
Asked: 2022-10-29T20:31:23+05:30 In:

Tan70°=tan20°+2tan50°

Tan70°=tan20°+2tan50°
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  1. As we all know,tan70°=tan(20+50)°\u200b\u200btan70°=(tan20°+tan50°)/1-tan20°tan50°tan70°-tan20°tan50°tan70°=tan20°+tan50°Also\xa0tan70°tan20°=tan70°cot70°=1Hencetan70°-tan50°=tan20°+tan50°So tan70°=tan20°+2tan50°

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