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Rosey Oza
Asked: 2022-11-01T14:06:49+05:30 In:

Suppose `n ( >=3)` persons are sitting in a row. Two of them are selected at random. The probability that they are not together is (A) `1- 2/n` (B) `2/(n-1)` (C) `1- 1/n` (D) nonoe of these
A. `1-(2)/(n)`
B. `(2)/(n-1)`
C. `1-(1)/(n)`
D. none of these

Suppose `n ( >=3)` persons are sitting in a row. Two of them are selected at random. The probability that they are not together is (A) `1- 2/n` (B) `2/(n-1)` (C) `1- 1/n` (D) nonoe of these
A. `1-(2)/(n)`
B. `(2)/(n-1)`
C. `1-(1)/(n)`
D. none of these
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  1. Correct Answer – A

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Mohan Dev Kulkarni
Asked: 2022-10-31T19:51:13+05:30 In:

Suppose `n ( >=3)` persons are sitting in a row. Two of them are selected at random. The probability that they are not together is (A) `1- 2/n` (B) `2/(n-1)` (C) `1- 1/n` (D) nonoe of these
A. `1-(1)/(n)`
B. `1-(2)/(n)`
C. `(2)/(n+1)`
D. `(2)/(n)`

Suppose `n ( >=3)` persons are sitting in a row. Two of them are selected at random. The probability that they are not together is (A) `1- 2/n` (B) `2/(n-1)` (C) `1- 1/n` (D) nonoe of these
A. `1-(1)/(n)`
B. `1-(2)/(n)`
C. `(2)/(n+1)`
D. `(2)/(n)`
Parabola
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1 Answer

  1. Correct Answer – B
    The total number of ways of selecting 2 persons out of n persons sitting in a row is `.^(n)C_(2)`.
    Number of ways in which two adjacent persons are selected from n persons sitting in a row =(n-1)
    Hence, required probability `=(.^(n)C_(2)-(n-1))/(.^(n)C_(2))=1-(2)/(n)`

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