Sum of all two digit numbers which when divided by 4 yield unity as remainder is.
A. 1012
B. 1201
C. 1212
D. 1210
A. 1012
B. 1201
C. 1212
D. 1210
Correct Answer – C
Sum of all two digit numbers which when divided by 4 yield unity as remainder is.
Sum of all two digit numbers which when divided by 4 yield unity as remainder is.
A. 1100
B. 1200
C. 1210
D. none of these
Sum of all two digit numbers which when divided by 4 yield unity as remainder is.
A. 1100
B. 1200
C. 1210
D. none of these
A. 1100
B. 1200
C. 1210
D. none of these
Sum of all two digit numbers which when divided by 4 yield unity as remainder is.
Sum of all two digit numbers which when divided by 4 yield unity as remainder is.
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The two-digit numbers, which when divided by `4`, yield `1` as remainder, are,
`13, 17, … 97`.
This series forms an A.P. with first term, `a = 13` and common difference, `d =4`.
Let `n` be the number of terms of the A.P.
It is known that the nth term of an A.P. is given by,` a_n = a + (n -1) d`.
`:. 97 = 13 + (n -1) (4)`
`=> 4 (n –1) = 84`
`=> n – 1 = 21`
`=> n = 22`
Now, `S_22 = n/2(2a+(n-1)d) = 22/2(2(13)+(22-1)4) = 11**110 = 1210`
So, the required sum will be `1210`.
Correct Answer – D