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Natwar Sathe
Asked: 2022-11-11T04:08:09+05:30 In:

STATEMENT-1: The equivalent mass of of `KMnO_(4)` in acidic medium is `(M)/(5)` where M=molecular mass of `KMnO_(4)`
STATEMENT-2: Equivalent mass is equal to product of molecular mass and change in oxidation number.

STATEMENT-1: The equivalent mass of of `KMnO_(4)` in acidic medium is `(M)/(5)` where M=molecular mass of `KMnO_(4)`
STATEMENT-2: Equivalent mass is equal to product of molecular mass and change in oxidation number.
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