State Kohlrausch law of independent migration of ions. Write an expression for the molar conductivity of acetic acid at infinite dilution according to Kohlrausch law.
`{:((b),”Calculate”,:,wedge^(@)m” for acetic acid.”),(,”Given that”,:,wedge^(@)m(HCl)=426 ” S ” “cm”^(2)mol^(-1)),(,,,wedge^(@) m(NaCl)=126 ” S ” cm^(2) mol^(-1)),(,,,wedge^(@) m(CH_(3)COONa)=91 ” S ” cm^(2)mol^(-1)):}`
`{:((b),”Calculate”,:,wedge^(@)m” for acetic acid.”),(,”Given that”,:,wedge^(@)m(HCl)=426 ” S ” “cm”^(2)mol^(-1)),(,,,wedge^(@) m(NaCl)=126 ” S ” cm^(2) mol^(-1)),(,,,wedge^(@) m(CH_(3)COONa)=91 ” S ” cm^(2)mol^(-1)):}`
(a) Kohlrausch law : It states that limiting molar conductivity of an eletrolyte can be reprsented as the individual contribution of the anion and cation of the electrolyte.
`wedge^(@)m(CH_(3)COOH) =lambda_(H^(+))^(@)lambda_(CH_(3)COO^(-))^(@)`
(b) `^_(m)^(@)(HCl)” “=lamda_(H^(+))^(@)+lamda_(Cl^(-))^(@)`
`wedge^(@)._(m)(NACl)” “=lambda^(@)._(Na^(+)+ lambda^(@)._(Cl)-`
`wedge^(@)._(m-)(CH_(3)COONa)” “= lambda^(@)CH_(3)COO^(-^(+))lambda^(@)._(Na^(+))`
`wedge^(@)._(m)(CH_(3)COONa)” “lambda^(@)._(H^(+))+lambda^(@)._(Cl^-)+^(@)._(CH_(3)COO^(-))+lambda^(@)._(Na^(+))- lambda^(@)._(Cl^-)-lambda^(@)._(Na`^(+))`
`” “=wedge^(@)._(m)(HCl)+wedge^(@)._(m)(CH_(3)COONa)- wedge^(@)._(m) Nacl`
`” “=426+91-126`
`” “=426+91-126`.