Given equations are{tex}\\frac{x}{2} + y = 0.8{/tex}{tex}\\frac{x + 2y}{2} = 0.8{/tex}.x + 2y = 1.6 …….. (i)and{tex}\\frac{7}{{x + \\frac{y}{2}}} = 10{/tex}\xa0{tex}\\frac{{7 \\times 2}}{{2x + y}} = 10{/tex}{tex}\\frac{{7}}{{2x + y}} = 5{/tex} 7 = 10x + 5y10x + 5y = 7 ………. (ii)Multiply first equation by 1010x + 20y = 16………… (iii)Subtracting the equations (ii) from (iii) , we get15y = 9{tex}y = \\frac{9}{{15}} = \\frac{3}{5}{/tex}Put value of y in (i){tex}x = 1.6 – 2\\left( {\\frac{3}{5}} \\right) = 1.6 – \\frac{6}{5} = \\frac{2}{5}{/tex}Solution is\xa0{tex}\\left( {\\frac{2}{5},\\;\\frac{3}{5}} \\right){/tex}