Solve the following quadratic equations by factorization:
\(x-\frac{1}{x-3}=3,x\neq0\)
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Solve the following quadratic equations by factorization:
\(x-\frac{1}{x-3}=3,x\neq0\)
Solve the following quadratic equations by factorization:
\(x-\frac{1}{x-3}=3,x\neq0\)
In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
\(x-\frac{1}{x-3}=3,x\neq0\)
⇒ x2 – 3x – 1 = 3x – 9
⇒ x2 – 6x + 8 = 0
⇒ x2 – 4x – 2x + 8 = 0
⇒ x(x – 4) – 2(x – 4) = 0
⇒ (x – 2)(x – 4) = 0
⇒ x = 2, 4