Solve the eq. x²-10x-2=0 by completing sq. Method
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
We have{tex}x^2 – 10x\xa0- 2 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 – 10x\xa0= 2{/tex}{tex}\\Rightarrow{/tex}\xa0x2 – 2 {tex}\\times{/tex}\xa0x {tex}\\times{/tex}\xa05 + 52 = 2 + 52 [adding 52 on both sides]{tex}\\Rightarrow{/tex}\xa0{tex}(x\xa0- 5)^2 = (2 + 25) = 27{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x\xa0- 5 ={/tex}{tex}\\pm \\sqrt { 27 } = \\pm 3 \\sqrt { 3 }{/tex} [taking square root on both sides]{tex}\\Rightarrow{/tex}\xa0{tex}x -\xa05 ={/tex}{tex}3 \\sqrt { 3 }{/tex} or x\xa0- 5 = -{tex}3 \\sqrt { 3 }{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x\xa0= (5 +{/tex}{tex}3 \\sqrt { 3 }{/tex}) or x\xa0= (5 -\xa0{tex}3 \\sqrt { 3 }{/tex}\xa0).Hence, (5 + {tex}3 \\sqrt { 3 }{/tex}) and (5 -{tex}3 \\sqrt { 3 }{/tex}) are the roots of the given equation.