Solution of 5th question of maths exercise 5.2
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Now we find that the common difference d=13-7=6 , d=6 And first term A = 7 And , last term An = 205 By using formula we have An = a + (n -1) d = = 205 = 7 + (n -1) 6 = ( n -1 ) 6 = 205 – 7 = n – 1= 198/6 = n = 33 + 1 = 34 Ans Hence , 34 th term is 205 I hope this is the helpful for u ……….
a=7,d=6,an=205an=a+(n-1)×d205=7+(n-1)×6205=7+6n-6205=1+6n6n=205-16n=204n=204÷6n=34My name is sarthak Bhardwaj