Sn denote the sum of the first n terms of an a.p prove that S12=3(S8-S4)
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So easy……S12 = n/2 ( 2a + (n – 1)d )S12 = 12/2 ( 2a + (12 – 1)d )S12 = 6 (2a + 11d)S12 = 12a + 66dSimilarly , we find value of S8 and S4S8 = 8a + 28dS4 = 4a + 6d3(S8 – S4)3( 8a + 28d – 4a – 6d)3( 4a + 22d)12a + 66d12a + 66d = S12S12 = 3(S8 – S4)Hence , proved.???