Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by
(a) A, B and C
(b) B, C and F
(c) A, B and F
(d) A, C and F
Correct option (b) B, C and F
Explanation:
At the start all the boys have equal number of cards, as shown below:
Now, F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B:
B gives 6 to D who passes on 1 to E.
Number of cards with D and E = 15 + 11 = 26
We can see that number of cards with B, C and F = 7 + 12 + 7 = 26