` sin 30 ^@ + icos 30 ^ @ ` को ध्रुवीय रूप व्यक्त कीजिये |
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` sin 30 ^ @ = cos 60 ^@ and cos 30 ^@ = sin 60 ^@ `
अब, ` z = sin 30 ^@ + i cos 30 ^@ = cos 60 ^@ + isin 60 ^@ `
` = 1 ( cos 60 ^@ + i sin 60 ^ @) `
` = 1* ( cos “” ( pi ) /( 3 ) + i sin “” ( pi ) /( 3) ) `
अतः ` r = 1 ` तथा ` theta = (pi ) /( 3 ) ` .
इसलिए , z का ध्रुवीय रूप है ` 1 * ( cos “” (pi ) / ( 3) + i sin”” ( pi ) /( 3 )) `