सिद्ध करे की
`(sec theta + tan theta)/(sec theta – tan theta)=(1+sin theta)/(cos theta)^(2)`
`(sec theta + tan theta)/(sec theta – tan theta)=(1+sin theta)/(cos theta)^(2)`
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बायाँ पक्ष `=(sec theta + tan theta)/(sec theta- tan theta)=(sec theta+ tan theta)/(sec theta – ktan theta)xx(sec theta + tan theta)/(sec theta + tan theta)`
`=(sec theta+ tan theta)^(2)/(sec^(2)-tan^(2)theta)=(sec theta+ tan theta)^(2)`
`=((1)/(cos theta)+(sin theta)/(cos theta))^(2)=(1+sin theta)/(cos theta)^(2)` दायाँ पक्ष