Show the formation of MgCl2, Na2O and MgO by the transfer of electrons.
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Mam how we full the block of these element
Atomic number of Sodium (Na) – 11Electronic configuration of Sodium – 1s2\xa02s2\xa02p6\xa03s1It has one valence electron, it will lose one electron to get octet configurationAtomic number of Oxygen (O) – 8Electronic configuration of Oxygen – 1s2\xa02s2\xa02p4It is two electrons short of octet configuration, thus it will gain two electrons.During the bond formation between Sodium and Oxygen, two Sodium atoms loses one electron each to Oxygen atom.2 Na -2e- → 2Na+O + 2e- → O-2\xa02Na+\xa0+ O-2\xa0→ Na2O\xa0Atomic number of Magnesium (Mg) – 12Electronic configuration of Magnesium – 1s2\xa02s2\xa02p6\xa03s2It has two valence electrons, it will lose two electrons to get octet configurationAtomic number of Oxygen (O) – 8Electronic configuration of Oxygen – 1s2\xa02s2\xa02p4It is two electrons short of octet configuration, thus it will gain two electrons.During the bond formation between Magnesium and Oxygen, one Magnesium atom loses two electrons to Oxygen atom.Mg -1e- → Mg2+O + 2e- → O-2\xa0Mg+2\xa0+ O-2\xa0→ MgO