Show that the three points `-2hati+3hatj+5hatk, hati+2hatj+3hatk, 7hati-hatk` are collinear
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Clearly,we have
`vec(AB)` = (position vector of B) – (position vector of A)
`= (hati + 2hatj + 3hatk) – (-2hati + 3hatj + 5hatk) = (3hati – hatj – 2hatk)`
`vec(BC) =` (position vector of C) – (position vector of B)
`= (7hati – 3hatk) – (hati + 2hatj +3hatk) =(6hati – 2hatj – 4hatk)`
`:. vec(AB) = 2vec(BC)` , which shows that `vec(AB) ` and `vec(BC)` are parallel vectors,
Hence the points A,B and C collinear.