Show that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5 where q is some integer
It\’s very easy fist of all take b in place of 6 a positive integer
Show that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5, where q is some integer.
Show that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5, where q is some integer.
Show that any positive odd integer is of the form 6q + 1 or 6q+3 or 6q+where q q is some integer
Show that any positive odd integer is of the form 6q + 1 or 6q+3 or 6q+where q q is some integer
Show that any positive odd integer is of the form 6q +1 or 6q+3or6q+5where q is integer some integer
Show that any positive odd integer is of the form 6q +1 or 6q+3or6q+5where q is integer some integer
Show that any positive odd integer is of the form 6q + 1, or 6q + 3 or 6q + 5, where q is some integer.
Show that any positive odd integer is of the form 6q + 1, or 6q + 3 or 6q + 5, where q is some integer.
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Let a is a positive odd integer and apply Euclid’s division algorithm
a = 6q + r, Where 0 ≤ r < 6
for 0 ≤ r < 6 probable remainders are 0, 1, 2, 3, 4 and 5.
a = 6q + 0
or a = 6q + 1
or a = 6q + 2
or a = 6q + 3
or a = 6q + 4
or a = 6q + 5 may be form
Where q is quotient and a = odd integer.
This cannot be in the form of 6q, 6q + 2, 6q + 4.
[all divides by 2]
Hence, any positive odd integer is of the form 6q + 1, or 6q + 3 or (6q + 5)
Show that any positive odd integer is of the form 6q+1,or 6q+3,or 6q+5, where q is some integer
Show that any positive odd integer is of the form 6q+1,or 6q+3,or 6q+5, where q is some integer
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Let a be any positive integer and b = 6∴ by Euclid’s division lemmaa = bq + r, 0≤ r and q be any integer q ≥ 0∴ a = 6q + r,where, r = 0, 1, 2, 3, 4, 5If a is even then then remainder by division of 6 is 0,2 or 4Hence r=0,2,or 4or A is of form 6q,6q+2,6q+4As, a = 6q = 2(3q), ora = 6q + 2 = 2(3q + 1), ora = 6q + 4 = 2(3q + 2).If these 3 cases a is an even integer.but if the remainder is 1,3 or 5 then r=1,3 or 5or A is of form 6q+1,,6q+3 or,6q+5Case 1:a = 6q + 1 = 2(3q) + 1 = 2n + 1,\xa0Case 2: a = 6q + 3 = 6q + 2 + 1,= 2(3q + 1) + 1 = 2n + 1,\xa0Case 3: a = 6q + 5 = 6q + 4 + 1= 2(3q + 2) + 1 = 2n + 1This shows that odd integer is of the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer.
Show that any positive odd integer is of the form 6q+1,or 6q+3, or 6q+5, where q is some integer
Show that any positive odd integer is of the form 6q+1,or 6q+3, or 6q+5, where q is some integer
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Let a be any positive integer and b = 6∴ by Euclid’s division lemmaa = bq + r, 0≤ r and q be any integer q ≥ 0∴ a = 6q + r,where, r = 0, 1, 2, 3, 4, 5If a is even then then remainder by division of 6 is 0,2 or 4Hence r=0,2,or 4or A is of form 6q,6q+2,6q+4As, a = 6q = 2(3q), ora = 6q + 2 = 2(3q + 1), ora = 6q + 4 = 2(3q + 2).If these 3 cases a is an even integer.but if the remainder is 1,3 or 5 then r=1,3 or 5or A is of form 6q+1,,6q+3 or,6q+5Case 1:a = 6q + 1 = 2(3q) + 1 = 2n + 1,\xa0Case 2: a = 6q + 3 = 6q + 2 + 1,= 2(3q + 1) + 1 = 2n + 1,\xa0Case 3: a = 6q + 5 = 6q + 4 + 1= 2(3q + 2) + 1 = 2n + 1This shows that odd integer is of the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer.
Show that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5 where q is sum some integer
Show that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5 where q is sum some integer
Let any posite odd integer be \’a\’.a=bq+r 0 <_ r < b b= 6 a= 6q+ r 0<_ r < 61) r= 0 , a= 6q2) r=1 , a= 6q+12) r=2 , a= 6q+23) r=3 , a= 6q+34) r=4 , a= 6q+45) r=5 , a= 6q+5Therefore, any positive integer can be in the form 6q, 6q+1, 6q+2, 6q+3, 6q+5.Here is your answer.