Show that 7-√5is irrational give that √5is irrational
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Seven underroot 5Put equal to a/b so Now underroot 5 is equal to a/7bTherefore a/7b is rationl no So5 also is a rational no But this contradict that underroot 5 is irrrational So ,our assumption is wrong and 7 underroot 5 is irrational no