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Akanksha Bala
Asked: 2022-11-06T11:04:42+05:30 In:

`S_((“rhombic”))+O_(2(g))rarr SO_(2(g)) , Delta H =-297.5 K J`
`S_((“monoclinic”))+O_(2(g))rarr SO_(2) , Delta H = – 300 K J`
The data can predict that –
A. Rhombic sulphur is yellow in colour
B. Monoclinic sulphur has metallic lusture
C. Monoclinic sulphur is more stable
D. `Delta H` transition of `S_(R )` to `S_(M)` is endothermic

`S_((“rhombic”))+O_(2(g))rarr SO_(2(g)) , Delta H =-297.5 K J`
`S_((“monoclinic”))+O_(2(g))rarr SO_(2) , Delta H = – 300 K J`
The data can predict that –
A. Rhombic sulphur is yellow in colour
B. Monoclinic sulphur has metallic lusture
C. Monoclinic sulphur is more stable
D. `Delta H` transition of `S_(R )` to `S_(M)` is endothermic
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1 Answer

  1. Correct Answer – D
    `S_(R )+O_(2)rarr SO_(2) , Delta H_(1)=-297.5 kJ`
    `S_(M)+O_(2)rarr SO_(2), Delta H_(2) = -300 kJ`
    `S_(R )rarr S_(M) , Delta H_(3) = ?`
    eq(iii) = eq(i) – eq(ii)
    `Delta H_(3)=-297.5-(-300)`
    `Delta H_(3)=+2.5 kJ` so, it endothermic process.

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