Rajeev throw three dice at the same time. Find the probability of getting a total of at most 6
1. 6/54
2. 53/54
3. 5/54
4. 7/54
5. 8/91
1. 6/54
2. 53/54
3. 5/54
4. 7/54
5. 8/91
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Correct Answer – Option 3 : 5/54
Given:
Rajeev = threw 3 dices at same time
Formula used:-
P(E) = Number of favorable outcomes/Total outcomes
Calculation:
Here, total number of possible outcomes = 6 × 6 × 6
⇒ No. of event of getting sum of at most of 6 is (1, 1, 1), (1, 1, 2), (1, 2, 1), (2, 1, 1), (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1), (1, 2, 2), (2, 1, 2), (1, 1, 4), (1, 4, 1), (4, 1, 1), (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1) and (2, 2, 2)
⇒ probability of getting total of at most 6 = 20/216
∴ probability of getting a total of at most 6 is 5/54