Rahim removes all the hearts from the cards. What is the probability of
i. Picking out an ace from the remaining pack.
ii. Picking out a diamond.
iii. Picking out a card that is not a heart.
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Rahim removes all the hearts from the cards. What is the probability of
i. Picking out an ace from the remaining pack.
ii. Picking out a diamond.
iii. Picking out a card that is not a heart.
Rahim removes all the hearts from the cards. What is the probability of
i. Picking out an ace from the remaining pack.
ii. Picking out a diamond.
iii. Picking out a card that is not a heart.
Total number of cards in the deck = 52.
Total number of hearts in the deck of cards =13.
When Hearts are removed, remaining cards = 52 – 13 = 39.
i)Picking out an Ace:
Number of outcomes favourable to Ace = 3 [∵ ♦ A, ♥ A, ♠ A, ♣ A]
Total number of possible outcomes from the remaining cards = 39
– after removing Hearts.
Probability = P(A)
\(=\frac{No.\,of\,favourable \,outcomes}{Total\, no.\,of \,outcomes}\)
\(=\frac{3}{39}= \frac{1}{13}\)
ii) Picking out a diamond:
Number of favourable outcomes to diamonds (♦) = 13
Total number of possible outcomes = 39
∴ p(♦) \(=\frac{3}{39}= \frac{1}{13}\)
iii) Picking out a card that is ‘not a heart’:
As all hearts are removed, the remain-ing cards are all non-heart cards. So the picked card will be definitely a non-heart card. So this is a sure event.
Hence its probability is one
P(E) \(=\frac{39}{39}= 1\)