Prove that : sin 54° + cos67° = sin23° + cos36°
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Prove that : sin 54° + cos67° = sin23° + cos36°
Prove that : sin 54° + cos67° = sin23° + cos36°
Taking LHS = sin54o + cos67o
We know that
cos θ = sin (90° – θ)
Here, θ = 67°
⇒ sin 54°+ sin (90° – 67°)
⇒ sin 54°+ sin 23°
We also know that
Sin θ = cos (90° – θ)
Here, θ = 54°
⇒ cos (90° – 54°) + sin 23°
⇒ cos 36°+ sin 23° = RHS
Hence Proved