Predict the sign of the entropy change for each of the following change of state.
(a) Hg(l) → Hg(g)
(b) AgNO3(s) → AgNO3(aq)
(c) I2(g) → I2(s)
(d) C(graphite) → C(diamond)
(a) +ve (because gases are highly random than liquid)
ΔS = S(g) – S(e) = +ve
(b) +ve (because ions are in more random state in aqueous solution as compared to solid state).
ΔS = S(aq) – S(s) = +ve .
(c) -ve (because gases are highly more random than solid).
ΔS = S(s) – S(g) = -ve.
(d) zero, diamond and graphite both are solid and in crystalline state.
(a) +ve (because gases are highly random than liquid)
ΔS = S(g) – S(e) = +ve
(b) +ve (because ions are in more random state in aqueous solution as compared to solid state.)
ΔS = s(aq) – S(s) = +ve
(c) -ve (because gases are highly more random than solid)
ΔS = S(s) – S(g) = -ve
(d) Zero
Diamond and graphite both are solid and in crystalline state.