A. 454
B. 804
C. 852
D. 908
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Correct Answer – D
For bcc, `d=(sqrt(3))/(2)a`
or `a=(2d)/(sqrt(3))=(2xx4.52)/(1.732)=5.219 Å=522` pm
`d=(ZxxM)/(a^(3)xxN_(0)xx10^(-30))=(2xx39)/((522)^(3)xx(6.02xx10^(23))xx10^(-30))`
Correct Answer – d
For fcc, `d= sqrt(3)/(2) a or a = (2d)/(sqrt(3)) =(2 xx 4.52)/(1.732)`
`= 3.219 Å = 522` pm
`rho = (Z xx M)/(a^(3) N_(0) xx 10^(-30))`
`= (2 xx 39)/((522)^(2) xx (6.025 xx 10^(23)) xx 10^(-30))`
`= 6.91 g//cm^(3) = 910 kg m^(-3)`
Correct Answer – d
For fcc, `d= sqrt(3)/(2) xx or a = (2d)/(sqrt(3)) = (2 xx 4.52)/(1.732)`
`= 5.129 Å = 522` pm
`rho = (Z xx M)/(a^(3) xx N_(0) xx 10^(-30))`
`= (2 xx 39)/((522)^(3) xx (0.23 xx 10^(23)) xx 10^(-30))`
`= 0.91 g//cm^(3)`
Correct Answer – D
For bcc, d`=sqrt(3)/(2)` a or `a=(2d)/sqrt(3)=(2xx4.52)/(1.732)=5.219overset(@)A`=522pm
`rho=(ZxxM)/(a^(3)xxN_(0)xx10^(-30))=(2xx39)/((522)^(3)xx(56.023xx10^(23))xx10^(-30))`
`=0.91g//cm^(3)=910kgm^(-3)`