One mole of an ideal gas undergoes a cyclic change ABCD. From the p-V diagram shown below, calculate the net work done in the process.
1 atm = 106 dyne cm-2.
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One mole of an ideal gas undergoes a cyclic change ABCD. From the p-V diagram shown below, calculate the net work done in the process.
1 atm = 106 dyne cm-2.
One mole of an ideal gas undergoes a cyclic change ABCD. From the p-V diagram shown below, calculate the net work done in the process.
1 atm = 106 dyne cm-2.
The work done in cyclic process is numerically equal to the area of the cycle.
As the cycle ABCD is traced in clock- wise direction, the work done is positive.
W = + area ABCD
= DC x AD
Now, DC = 4 – 3 = 3 litres
= 3 x 103 cm3
( ∴1 lit = 103 cm3)
and AD = 5 – 2 = 3 atm
= 3 x 106 dyne cm-1
work done = 3 x 103 x 3 x 106
= 9 x 109 ergs.