Molarity of a solution obtained by mixing 800 mL of 0.6 M HCl with 200 mL of 1 M HCl will be
(a) 0.4 M
(b) 1.6 M
(c) 0.68 M
(d) 1.68 M
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Molarity of a solution obtained by mixing 800 mL of 0.6 M HCl with 200 mL of 1 M HCl will be
(a) 0.4 M
(b) 1.6 M
(c) 0.68 M
(d) 1.68 M
Molarity of a solution obtained by mixing 800 mL of 0.6 M HCl with 200 mL of 1 M HCl will be
(a) 0.4 M
(b) 1.6 M
(c) 0.68 M
(d) 1.68 M
Answer is : (c) 0.68 M
M = \(\frac{M_1V_1+M_2V_2}{V_1+V_2}\)
\(=\frac{0.6\times 800+1\times 200}{1000}\)
\(=\frac{480+200}{1000}\)
\(=\frac{680}{1000}\)
= 0.68 M