Correct Answer – 4
For BCC, `sqrt(3)a=4r, r=(sqrt(3)xx351)/(4)=152` pm

Correct Answer – B
In case of body centred cubic (bcc) crystal,
`asqrt3=4r`
Given, edge length, a=351 pm
Hence, atomic radius of lithium,
`r=(asqrt3)/(4)=(351xx1.732)/(4)`
`=151.98″ pm”`

Correct Answer – D
For b.c.c structure, `sqrt(3)a=4r`
`r=sqrt(3)/4a=sqrt(3)/4xx351=152″pm”`

Correct Answer – A
Since lithium crystallises in a body centred cubic crystal,
Atomic radius `(r)=(sqrt(3)a)/4=a/(2sqrt(2))`
`=sqrt(3)/4xx351″pm”=151.8 “pm”`