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Rimi Mutti
Asked: 2022-11-11T13:17:45+05:30 In:

Linear momentum of an object can be expressed as `vecP= (4 cos t)hati+( 4 sin t)hatj`. Angle between the forces acting on the object and its linear momentum is :
A. `(pi)//(2)`
B. `(pi)//(4)`
C. `(3pi)//(4)`
D. `pi`

Linear momentum of an object can be expressed as `vecP= (4 cos t)hati+( 4 sin t)hatj`. Angle between the forces acting on the object and its linear momentum is :
A. `(pi)//(2)`
B. `(pi)//(4)`
C. `(3pi)//(4)`
D. `pi`
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1 Answer

  1. Correct Answer – A
    `” “vecP=(4 cos t)hati + (4 sin t)hatj`
    `therefore” “vecF= (dvecP)/(dt)=(-4 sin t)hati +(4 cos t)hatj`
    `thereforevecF. vecP= 0 rArr theta = pi//2`

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