Let `veca=(1,1,-1), vecb=(5,-3,-3)` and `vecc=(3,-1,2)`. If `vecr` is collinear with `vecc` and has length `(|veca+vecb|)/(2)`, then `vecr` equals
A. `+-3vecc`
B. `+-3/2vecc`
C. `+-vecc`
D. `+-2/3vecc`
A. `+-3vecc`
B. `+-3/2vecc`
C. `+-vecc`
D. `+-2/3vecc`
Correct Answer – C
We have, `vecr=lambdavecc`
Given, `|vecr|=|lambda||vecr|`
`therefore |6hati-2hatj-hatk|=2|lambda||3hati-hatj+2hatk|`
`therefore sqrt(56) = 2|lambda|sqrt(14)`
`therefore lambda=+-1`
`therefore vecr=+-vecc`