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Atul Prasoon Boase
Asked: 2022-11-10T06:36:20+05:30 In:

Let ` f : R to R` be a function given by `f(x+y) = f(x) + f(y) ` for all x,y `in`R such that `f(1)= a` Then, `f (x)=`
A. `a^(x)`
B. `ax`
C. `a^(x)`
D. none of these

Let ` f : R to R` be a function given by `f(x+y) = f(x) + f(y) ` for all x,y `in`R such that `f(1)= a` Then, `f (x)=`
A. `a^(x)`
B. `ax`
C. `a^(x)`
D. none of these
Parabola
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1 Answer

  1. Correct Answer – A
    We know that the general expression for the function satsifying `f(x+y) = f(x) f(y) ` for all x,y `in R,” “[because f(1) =a]`

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Nagma Devi
Asked: 2022-11-03T11:32:07+05:30 In:

Let ` f : R to R` be a function given by `f(x+y) = f(x) + f(y) ` for all x,y `in`R such that `f(1)= a` Then, `f (x)=`
A. `a^(x)`
B. `ax`
C. `a^(x)`
D. `a+x`

Let ` f : R to R` be a function given by `f(x+y) = f(x) + f(y) ` for all x,y `in`R such that `f(1)= a` Then, `f (x)=`
A. `a^(x)`
B. `ax`
C. `a^(x)`
D. `a+x`
Parabola
Leave an answer

Leave an answer

Browse

1 Answer

  1. Correct Answer – B
    We know that the general formula for the function
    `f: R to R ` given by `f (x)f(y)` for all x,y `in`R
    `f(x) = xf(1) rArr f (x) =ax” “[because f(1) =a]`

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