Let a,b and c be three non-zero vectors which are pairwise non-collinear. If a+3b is collinear with c and b+2c is collinear with a, then a+3b+6c is
A. a+c
B. a
C. `c`
D. 0
A. a+c
B. a
C. `c`
D. 0
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Correct Answer – D
As, a+3b is collinear with c.
`thereforea+3b=lamdac` . . . (i)
Also, b+2c is collinear with a.
`implies b+2c=mua` . . (ii)
From eq. (ii), we get
`a+3b+6c=(lamda+6)c` . .. (iii)
From eq. (ii), we get
`a+3b+6c=(1+3mu)a` . . (iv)
From eqs. (iii) and (iv), we get
`therefore(lamda+6)c=(1+3mu)a`
Since, a is not collinear with c.
`implies lamda+6=1+3mu=0`
from eq. (iv), we get
`a+3b+6c=0`.