Is it true that for any sets A and B,

P (A) ∪ P (B) = P (A ∪ B)?

Justify your answer.

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False

Let A = {0, 1} and B = {1, 2} 7

∴ A ∪ B = {0, 1, 2}

P(A) = {Φ, {0}, {1},{0, 1}}

P(B) = {Φ, {1}, {2}, {1, 2}}

P(A ∪ B) = {Φ, {0}, {1}, {2}, {0, 1}, {1, 2}, {0, 2}, {0, 1, 2}}

P(A) ∪ P(B) = {Φ, {0}, {1}, {0, 1}, {2}, {1, 2}}

∴ P(A) ∪ P(B) ≠ P(A ∪ B)