Is 51 tearm of the AP 5,8,11
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Here the first term; a = 5Common difference; d = 11 – 8 = 8 – 5 = 3So, nth term is given by;tn = a + (n − 1)d = 5 + (n − 1) × 3Now to prove whether 51 is term of this A.P, taking tn = 5151 = 5 + (n − 1) × 3⇒ 51 = 5 + 3n − 3⇒ 3n = 51 + 3 − 5⇒ 3n = 49n = 49/33Now we know that number of terms can\’t be in fraction.So, 51 is not term of this A.P.