In triangle ABC,right angled at B, if tanA=1/√3,find the value of(i) sinAcosC+cosAsinC
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If tanA = 1/√3Than In triangle by pytagoreous theoream hypoteneous = 2.. Than in triangle ABCsinA = 1/2SinC = √3/2CosA = √3/2CosC = 1/2..A/Q= (1/2*1/2)+(√3/2*√3/2)= 1/4+3/4= 4/4= 1