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Swati Karim Das
Asked: 2022-11-11T20:36:11+05:30 In:

In the reaction: `Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`, the equivalent weight of `Na_(2)S_(2)O_(3)` will be: (M= molecular weight of `Na_(2)S_(2)O_(3))`
A. `(M)/(4)`
B. `(M)/(8)`
C. `(M)/(1)`
D. `(M)/(2)`

In the reaction: `Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`, the equivalent weight of `Na_(2)S_(2)O_(3)` will be: (M= molecular weight of `Na_(2)S_(2)O_(3))`
A. `(M)/(4)`
B. `(M)/(8)`
C. `(M)/(1)`
D. `(M)/(2)`
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  1. Correct Answer – b

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Bhola Lalit Rajagopal
Asked: 2022-11-09T23:33:28+05:30 In:

In the reaction: `Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`, the equivalent weight of `Na_(2)S_(2)O_(3)` will be: (M= molecular weight of `Na_(2)S_(2)O_(3))`
A. (a)`M//4`
B. (b)`M//8`
C. (c )`M//1`
D. (d)`M//2`

In the reaction: `Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`, the equivalent weight of `Na_(2)S_(2)O_(3)` will be: (M= molecular weight of `Na_(2)S_(2)O_(3))`
A. (a)`M//4`
B. (b)`M//8`
C. (c )`M//1`
D. (d)`M//2`
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1 Answer

  1. Correct Answer – B
    `Na_(2) overset(+2)(S_(2) O_(3)) rarr Na_(2) overset(+6)(S O_(4))`
    the total change in oxidation number `=4xx2=8`
    `:. E_(Na_(2)S_(2)O_(3))=(mol. Wt.)/(v.f)=M/8`

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