In the reaction `AB_(2)(l)+3X_(2)(g)hArrAX_(2)(g)+2BX_(2)(g) DeltaH=-2700` kcal per mole. Of `AB_(2)(l)`. The entalpies of formation of `AX_(2)(g)` and `BX_(2)(g)` are in the ratio of `4 : 3` and have opposite sign. The value of `DeltaH_(f)^(@)(AB_(2)(l))=30 kcal//mol`. Then :
A. `DeltaH_(f)^(@)(AX_(2))=-96kcal//mol`
B. `DeltaH_(f)^(@)(BX_(2))=+480kcal//mol`
C. `K_(p)=K_(c)` and `DeltaH_(f)^(@)(AX_(2))=+480kcal//mol`
D. `K_(p)=K_(c) ” RT”` and `DeltaH_(f)^(@)(AX_(2))+DeltaH_(f)^(@)(BX_(2)=-240kcal//mol`
A. `DeltaH_(f)^(@)(AX_(2))=-96kcal//mol`
B. `DeltaH_(f)^(@)(BX_(2))=+480kcal//mol`
C. `K_(p)=K_(c)` and `DeltaH_(f)^(@)(AX_(2))=+480kcal//mol`
D. `K_(p)=K_(c) ” RT”` and `DeltaH_(f)^(@)(AX_(2))+DeltaH_(f)^(@)(BX_(2)=-240kcal//mol`
Correct Answer – C