In the given figure, AL is parallel to DC and E Is mid point of BC. Show that triangle EBL Is congruent to triangle ECD.
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In the given figure, AL is parallel to DC and E Is mid point of BC. Show that triangle EBL Is congruent to triangle ECD.
In the given figure, AL is parallel to DC and E Is mid point of BC. Show that triangle EBL Is congruent to triangle ECD.
From the adjacent figure
AL // CD and E is the midpoint of BC.
i.e., BE = EC
from ΔBEL & ΔCED.
∠B = ∠C [ ∵ Alternate interior angles]
∠DEC = ∠BEL [ ∵ vertically opposite, angles]
∴ By A.S.A rule
Δ EBL ≅ Δ ECD.