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Raj Gobin
Asked: 2022-11-08T04:51:30+05:30 In:

In the crystal lattice of `CsCl,CS^(+)` ions are present at the
A. `Cs^(+)` forms a simple cubic lattice. `Cl^(-)` forms a simple cubic lattice
B. `Cl^(-)` occupies body centre of `Cs^(+)`
C. `Cs^(+)` occupies body centre of `Cl^(-)`
D. It is impossible for `Cl^(-)` to occupy body centre of `Cs^(+)` because the body centre void of `Cs^(+)` is smaller than the `Cl^(-)` ion size.

In the crystal lattice of `CsCl,CS^(+)` ions are present at the
A. `Cs^(+)` forms a simple cubic lattice. `Cl^(-)` forms a simple cubic lattice
B. `Cl^(-)` occupies body centre of `Cs^(+)`
C. `Cs^(+)` occupies body centre of `Cl^(-)`
D. It is impossible for `Cl^(-)` to occupy body centre of `Cs^(+)` because the body centre void of `Cs^(+)` is smaller than the `Cl^(-)` ion size.
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1 Answer

  1. Correct Answer – A::B::C
    In CsCl, the coordination number is 8. Here `Cl^(-)` forms BCC packing with `Cs^(+)` occupying body centre voids or `Cs^(+)` forms SCC packing with `Cl^(-)` occupying body centred voids.

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