In normal YDSE experiment maximum intensity is `4I_(0)` in Column I, y-coordinate is given corresponding to centre line In Coloum II resultant intensities are given Match the two columns.
`{:(,”Column I”,,”Column II”),(“A”,y=(lambdaD)/d,,p. I=I_(0)),(“B”,y=(lambdaD)/(2d),,q. I=2I_(0)),(“C”,y=(lambdaD)/(3d),,r. I=4I_(0)),(“D”,y=(lambdaD)/(4d),,s. I=zero):}`
`{:(,”Column I”,,”Column II”),(“A”,y=(lambdaD)/d,,p. I=I_(0)),(“B”,y=(lambdaD)/(2d),,q. I=2I_(0)),(“C”,y=(lambdaD)/(3d),,r. I=4I_(0)),(“D”,y=(lambdaD)/(4d),,s. I=zero):}`
Correct Answer – A::B::C::D
`Deltax=(yd)/D,phi=(2pi)/lambda.Deltax and I=4I_(0)”cos”^(2)phi/2`