In Fig., If AB ⊥ BC and DE ⊥ AC, prove that ΔCED ~ ΔABC
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
In Fig., If AB ⊥ BC and DE ⊥ AC, prove that ΔCED ~ ΔABC
In Fig., If AB ⊥ BC and DE ⊥ AC, prove that ΔCED ~ ΔABC
Given
AB⏊BC, DC ⏊ BC and DE ⏊AC
To prove:-
ΔCED ~ΔABC
Proof:-
∠BAC + ∠BCA = 90° …………..(i) (By angle sum property)
And, ∠BCA + ∠ECD = 90°……(ii) (DC ⏊ BC given)
Compare equation (i) and (ii)
∠BAC = ∠ECD……………..(iii)
In ΔCED and ΔABC
∠CED = ∠ABC (Each 90°)
∠ECD = ∠BAC (From equation iii)
Then, ΔCED ~ΔABC.