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Pinky Bhavsar
Asked: 2022-10-30T07:28:23+05:30 In:

In an ionic solid `r_((+))=1.6A` and `r_((-))=1.864A`. Use the radius ratio to determine the edge length of the cubic unit cell in `A`.
A. 4
B. `2sqrt(3)`
C. `3sqrt(3)`
D. `(4)/(sqrt(3))`

In an ionic solid `r_((+))=1.6A` and `r_((-))=1.864A`. Use the radius ratio to determine the edge length of the cubic unit cell in `A`.
A. 4
B. `2sqrt(3)`
C. `3sqrt(3)`
D. `(4)/(sqrt(3))`
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  1. Correct Answer – 1
    `(r_(+))/(r_(_))=(1.6)/(1.864)=0.858`
    So, it is `CsCl` type of unit cell
    So `sqrt(3)a=2(r_(+)+r_(_))`
    So, `a=(2(1.864+1.6))/(sqrt(3))Å=2xx2Å=4Å`

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