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Yadunandan Fardeen Venkataraman
Yadunandan Fardeen Venkataraman
Asked: 3 years ago2022-11-04T20:38:35+05:30 2022-11-04T20:38:35+05:30In: General Awareness

In a YDSE, the separation between slits is `2 mm` where as the distance of screen from the plane of slits is `2.5 m`. Light of wavelengths in the range `200-800 nm` is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at `1 mm` from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.
A. `4000Å`
B. `5000Å`
C. `6000Å`
D. `8000Å`

In a YDSE, the separation between slits is `2 mm` where as the distance of screen from the plane of slits is `2.5 m`. Light of wavelengths in the range `200-800 nm` is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at `1 mm` from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.
A. `4000Å`
B. `5000Å`
C. `6000Å`
D. `8000Å`
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  1. d58a4
    2022-11-03T04:41:53+05:30Added an answer about 3 years ago

    Correct Answer – D

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Nishi D’Alia
Nishi D’Alia
Asked: 3 years ago2022-11-01T02:00:23+05:30 2022-11-01T02:00:23+05:30In: General Awareness

In a YDSE, the separation between slits is `2 mm` where as the distance of screen from the plane of slits is `2.5 m`. Light of wavelengths in the range `200-800 nm` is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at `1 mm` from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.

In a YDSE, the separation between slits is `2 mm` where as the distance of screen from the plane of slits is `2.5 m`. Light of wavelengths in the range `200-800 nm` is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at `1 mm` from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.
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  1. 8deee
    2022-11-11T18:14:15+05:30Added an answer about 3 years ago

    Correct Answer – `[8000 Å, 4000 Å 2666.7 Å……8000 Å` (infrared), `2666.7 Å` (ultraviolet)]

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Darpan Shukla
Darpan Shukla
Asked: 3 years ago2022-10-29T00:59:06+05:30 2022-10-29T00:59:06+05:30In: General Awareness

In a YDSE, the separation between slits is `2 mm` where as the distance of screen from the plane of slits is `2.5 m`. Light of wavelengths in the range `200-800 nm` is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at `1 mm` from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.

In a YDSE, the separation between slits is `2 mm` where as the distance of screen from the plane of slits is `2.5 m`. Light of wavelengths in the range `200-800 nm` is allowed to fall on the slits. Find the wavelengths in the visible region that will be present on the screen at `1 mm` from central maximum. Also find the wavelength that will be present at that point of screen in the infrared as well as in the ultraviolet region.
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  1. e0c56
    2022-11-01T23:29:10+05:30Added an answer about 3 years ago

    `d=2 mm, D=2.5 m, x=1 mm`
    For present wavelengths, use condition of maxima
    `y=(nDlambda)d`
    `1xx10^(-3)=(nxx2.5lambda)/(2xx10^(-3))`
    `lambda=2/2.5xx10^(-6)/n`
    `=(0.8xx10^(-6))/nm`
    `=800/n nm`
    `n=1, lambda=800 nm`
    `n=2, lambda=400 nm`
    `n=3, lambda=800/3~=267 nm`
    `n=4, lambda=200 nm`
    Wavelength in infrared region`=800 nm`
    Wavelength in ultraviolet region `=200 nm, 267 nm`
    Wavelength in visible region `=400 nm`

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