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In a cricket match, a batsman hits a boundary 6 times out of 3 balls he plays. Find the probability that he did not hit a boundary.
In a cricket match, a batsman hits a boundary 6 times out of 3 balls he plays. Find the probability that he did not hit a boundary.
It is given that
Number of times boundary was hit = 6
Total number of balls played = 30
So we get
Number of times boundary was not hit = 30 – 6 = 24
We know that
Probability that the batsman did not hit a boundary = number of times boundary was not hit/ total number of balls played
By substituting the values
Probability that the batsman did not hit a boundary = 24/30
By division
Probability that the batsman did not hit a boundary = 4/5 = 0.8
Correct Answer – C
Total number of balls thrown = 30 .
Number of times the boundary is hit = 6.
Number of times the ball does not hit the boundary = 30 – 6 = 24 .
Required Probability= `(24)/(30) = (4)/(5)` .