B. 25

Given:

Total number of students are 60

Students who play cricket and tennis are 25 and 20 respectively

Students who play both the games are 10

To find: number of students who play neither

Let S be the total number of students, C and T be the number of students who play cricket and tennis respectively

n(S) = 60, n(C) = 25, n(T) = 20, n(C ∩ T) = 10

Number of students who play either of them = n(C ∪ T)

= n(C) + n(T) – n(C ∩ T)

= 25 + 20 – 10

= 35

Number of student who play neither

= Total – n(C ∪ T)

= 60 – 35

= 25

Hence, there are 25 students who play neither cricket nor tennis.

According to the question,

Total number of students = 60

Students who play cricket = 25

Students who play tennis = 20

Students who play both the games = 10

To find: number of students who play neither

Let the total number of students = S

Let the number of students who play cricket = C

Let the number of students who play tennis = T

n(S) = 60, n(C) = 25, n(T) = 20, n(C ∩ T) = 10

So, Number of students who play either of them,

n(C ∪ T) = n(C) + n(T) – n(C ∩ T)

= 25 + 20 – 10

= 35

Hence, Number of student who play neither = Total – n(C ∪ T)

= 60 – 35

= 25

Therefore, there are 25 students who play neither cricket nor tennis.

Let C be the set of students who play cricket and T be the set of students who play tennis.
Then, `n (U) = 60, n (C ) = 25, n(T) = 20` and `n(C nn T) = 10`
`:. N(C uu T) = n(C ) + n (T) – n (C nn T)`
`= 25+ 20 – 10 = 35`
`:.` Number of students who play neither `= n(U) – n(C uu T)`
`= 60 – 35 = 25`

Let C be the set of students who play cricket and T be the set of students who play tennis.

n(U) = 60, n(C) = 25, n(T) = 20, and n(C ∩ T) = 10

n(C ∪ T) = n(C) + n(T) – n(C n T) = 25 + 20 – 10 = 35