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Akshay Baber Sengupta
Asked: 2022-11-01T09:51:13+05:30 In:

If `vec(a)` and `vec(b)` are vectors such that `|vec(a)|=sqrt(3), |vec(b)|=2` and `vec(a).vec(b)=sqrt(6)` then the angle between `vec(a) and vec(b)` is
A. `(pi)/(6)`
B. `(pi)/(3)`
C. `(pi)/(4)`
D. `(2pi)/(3)`

If `vec(a)` and `vec(b)` are vectors such that `|vec(a)|=sqrt(3), |vec(b)|=2` and `vec(a).vec(b)=sqrt(6)` then the angle between `vec(a) and vec(b)` is
A. `(pi)/(6)`
B. `(pi)/(3)`
C. `(pi)/(4)`
D. `(2pi)/(3)`
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1 Answer

  1. Correct Answer – C
    `cos theta=(vec(a).vec(b))/(|vec(a)||vec(b)|)=(sqrt(6))/(sqrt(3)xx2)=(1)/(sqrt(2))rArr theta=(pi)/(4)`.

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