If two vertics of equilateral triangle are (4,3)(-4,3) find third vertex
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Let the vertices be (x,y)then distance between (x,y) & (4,3) is=……(1)and distance between (x,y) & (-4,3) is=……….(2)distance between (4,3) &(-4,3) is==√(8)²=8then(1)=(2)or (x-4)²=(x+4)²or x²-8x+16=x²+8x+16or 16x=0or x=0again (1)=8or (x-4)²+(y-3)²=64………(3)putting the value of x in (3)then (0-4)²+(y-3)²=64or (y-3)²=64-16or (y-3)²=48or y-3=(+-)4√3or y=3(+-)4√3if we choose y as 3+4√3 then origin isn\’t lies interior of triangleSo required vertex is(0,3-4√3)…..(ans)by aniket?