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Rachel Saurabh Samuel
Asked: 2022-11-09T03:52:49+05:30 In:

If the density of a 1-ltre solution of `98% H_(2)SO_(4) (wt.//vol.)` is `1.88 g mol^(-1)`, the molality of the solution will be
A. `13.13`
B. `10.10`
C. `11.11
D. `12.12`

If the density of a 1-ltre solution of `98% H_(2)SO_(4) (wt.//vol.)` is `1.88 g mol^(-1)`, the molality of the solution will be
A. `13.13`
B. `10.10`
C. `11.11
D. `12.12`
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  1. Correct Answer – 3
    `98% H_(2)SO_(4) (wt.//vol.)` implies that every `100 mL` of solution contains `98 g` of `H_(2)SO_(4)`. Thus
    `n_(H_(2)SO_(4))=(mass_(H_(2)SO_(4)))/(molar mass_(H_(2)SO_(4)))`
    `=(98 g)/(98 g//mol)=1 mol`
    Mass of solution =`(Volume)_(“soln”)xx(“density”)_(“soln”)`
    `=(100 mL)(1.88 g mL^(-1))`
    `=188 g`
    Mass of solvent =(Mass of solution) – (Mass of solute)
    `=(188 g) – (98 g)`
    `=90 g`
    Molality (m)`= n_(H_(2)SO_(4))/g_(“solvent”)xx(1000 g)/(kg)`
    `=(1 mol)/(90 g)xx(1000 g)/(kg)`
    `=11.11 m`

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