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Aadil Choudhry
Asked: 2022-11-11T10:53:31+05:30 In:

If the bond dissociation energies of XY, `X_(2)` and `Y_(2)` (all diatomic molecules) are in the ratio of `1 : 1 : 0.5` and `Delta_(f) H` for the formation of XY is `- 200 kJ ” mole”^(-1)`. The bond dissociation energy of `X_(2)` will be
A. 100 kJ `mol^(-1)`
B. 800 kJ `mol^(-1)`
C. 300 kJ `mol^(-1)`
D. 400 kJ `mol^(-1)`

If the bond dissociation energies of XY, `X_(2)` and `Y_(2)` (all diatomic molecules) are in the ratio of `1 : 1 : 0.5` and `Delta_(f) H` for the formation of XY is `- 200 kJ ” mole”^(-1)`. The bond dissociation energy of `X_(2)` will be
A. 100 kJ `mol^(-1)`
B. 800 kJ `mol^(-1)`
C. 300 kJ `mol^(-1)`
D. 400 kJ `mol^(-1)`
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  1. Correct Answer – B
    `XYrarrX_((g))+Y_((g)), DeltaH=+”a kJ/mole”^(-1)” ………(i)”`
    `X_(2)rarr2X, DeltaH=+” a kJ/mole …..(ii)”`
    `Y_(2)rarr2Y, DeltaH=+0.5″ a kJ/mole …….(iii)”`
    `(1)/(2)xx(ii)+(1)/(2)xx(iii)-(i)`, gives
    `(1)/(2)X_(2)+(1)/(2)Y_(2)rarrXY,`
    `DeltaH=(+(a)/(2)+(0.5)/(2)a-a)”kJ/mole”`
    `+(a)/(2)+(0.5a)/(2)-a=-200`
    a = 800

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Anees Nakul Chhabra
Asked: 2022-11-01T10:40:27+05:30 In:

If the bond dissociation energies of XY , `X_(2)` and `Y_(2)` ( all diatomic molecules )are in the ratio `1:1 : 0.5` and `DeltaH _(f) ` for the formation of XY of `- 200 kJ mol^(-1)` , the bond dissociation energy of `X_(2)` will be
A. `100 kJ mol^(-1)`
B. `200 kJ mol^(-1)`
C. ` 400 kJ mol^(-1)`
D. ` 800 kJmol^(-1)`

If the bond dissociation energies of XY , `X_(2)` and `Y_(2)` ( all diatomic molecules )are in the ratio `1:1 : 0.5` and `DeltaH _(f) ` for the formation of XY of `- 200 kJ mol^(-1)` , the bond dissociation energy of `X_(2)` will be
A. `100 kJ mol^(-1)`
B. `200 kJ mol^(-1)`
C. ` 400 kJ mol^(-1)`
D. ` 800 kJmol^(-1)`
Parabola
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  1. Correct Answer – D
    Suppose bond dissociation energy of XY `=akJ mol^(-1) , i.e., `BE ( XY )= a . Then BE `9X_(2)0= a, BE(Y_(2))= 0.5 a`
    Aim `: (1)/(2) X_(2)+ (1)/(2) Y_(2) rarr XY`
    `Delta_(r)H = BE` ( Reactants ) – BE ( Products )
    `= [ (1)/(2) BE (X_(2)) + (1)/(2) BE(Y_(2)) ] = BE(XY)`
    `:. – 200 = ((a)/(2) + (0.5a)/( 2)) -a`
    or ` – 200 = – 0.25 a` or `a= 800 kJ mol^(-1)`

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Balaji Iqbal Dugar
Asked: 2022-10-29T16:47:47+05:30 In:

If the bond dissociation energies of `XY,X_(2)` and `Y_(2)(` all diatomic molecules `)` are in the ratio `1:1:0.5` and `Delta_(f)H` of `XY` is `-200 kJ mol^(-1)`. The bond dissociation energy of `X_(2)` will be `:`
A. `800kJ mol^(-1)`
B. `200kJ mol^(-1)`
C. `300 kJ mol^(-1)`
D. `400kJ mol^(-1)`

If the bond dissociation energies of `XY,X_(2)` and `Y_(2)(` all diatomic molecules `)` are in the ratio `1:1:0.5` and `Delta_(f)H` of `XY` is `-200 kJ mol^(-1)`. The bond dissociation energy of `X_(2)` will be `:`
A. `800kJ mol^(-1)`
B. `200kJ mol^(-1)`
C. `300 kJ mol^(-1)`
D. `400kJ mol^(-1)`
Parabola
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  1. Correct Answer – A
    Given `(1)/(2)X_(2)+(1)/(2)Y_(2) rarr XY,DeltaH=-200kJ mol^(-1)` Let bond dissociation energy of `X_(2),Y_(2)` and `XY` be `a:(a)/(2)a(` the ratio given `)`
    `X_(2) rarr 2X, DeltaH=a ….(1)`
    `Y_(2) rarr 2Y, DeltaH=(a)/(2) …(2)`
    `XY rarr X+Y, DeltaH=a …..(3)`
    By `eq. (1)+(2)-(3)xx2`
    `X_(2)+Y_(2) rarr 2XY`
    `Delta H=a+(a)/(2)-2a`
    or `(1)/(2)X_(2)+(1)/(2)Y_(2) rarr XY,`
    `DeltaH=(a)/(2)+(a)/(2)-a=-(a)/(4)`
    `:. -(a)/(4)=-200`
    `:. a=800kJ mol^(-1)`

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