If sum and product of zeroes given 1/4,-1 respectively find its quadratic polynomial how do we find
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Sorry the first two lines be like that ?let the two zeroes be in the form of alpha and beeta.
Use formula x^2 – (a+b)x + (a×b) =0___X^2 – (1/4)x + (-1)=0 ____ take 1/ 4 comon____ 1/4(4x^2 – x – 4 )=0 ____ 4x^2 – x – 4=0
Let the sum of zeroes be alpha and product of zeroes be beeta…. Then A/Q, alpha+beeta=1/4 and alphaXbeeta=-1… Now put sum and product in these ? x²-(alpha+beeta)x+alpha.beeta……we get,x²-1/4x+(-1)..i,e. the required polynomial is x²-1/4x-1.