If sina+sinb+sinc=3 Find value of cosa +cosb+ cosc
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Maximum value of sin Ф is 1.So sinA+sinB+sinC=3 means sin A = 1sin B = 1sin C = 1Thus, A = B = C = 90 degreecos A = cos 90 = 0cos B = cos 90 = 0cos C = cos 90 = 0cos A + cos B +cos C = 0